(3/7x+4)=(1/7x-2)

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Solution for (3/7x+4)=(1/7x-2) equation:



(3/7x+4)=(1/7x-2)
We move all terms to the left:
(3/7x+4)-((1/7x-2))=0
Domain of the equation: 7x+4)!=0
x∈R
Domain of the equation: 7x-2))!=0
x∈R
We get rid of parentheses
3/7x-((1/7x-2))+4=0
We calculate fractions
21x/49x^2+(-((1*7x)/49x^2+4=0
We add all the numbers together, and all the variables
21x/49x^2+(-((+1*7x)/49x^2+4=0
We calculate fractions
We do not support expression: x^4

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