(3/8)/40=9/y

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Solution for (3/8)/40=9/y equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(3/8)/40 = 9/y // - 9/y

(3/8)/40-(9/y) = 0

(3/8)/40-9*y^-1 = 0

-9*y^-1 = -3/320 // : -9

y^-1 = 1/960

-1 < 0

1/(y^1) = 1/960 // * y^1

1 = 1/960*y^1 // : 1/960

960 = y^1

y = 960

y = 960

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