(3/8)f+(1/2)=6(1/16f-3)

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Solution for (3/8)f+(1/2)=6(1/16f-3) equation: 



(3/8)f+(1/2)=6(1/16f-3)

We move all terms to the left:

(3/8)f+(1/2)-(6(1/16f-3))=0



Domain of the equation: 8)f!=0

f!=0/1

f!=0

f∈R





Domain of the equation: 16f-3))!=0

f∈R



We add all the numbers together, and all the variables

(+3/8)f-(6(1/16f-3))+(+1/2)=0

We multiply parentheses

3f^2-(6(1/16f-3))+(+1/2)=0

We get rid of parentheses

3f^2-(6(1/16f-3))+1/2=0

We calculate fractions


3f^2+()/16f+16f/16f=0

Fractions to decimals

3f^2+()/16f+1=0

We multiply all the terms by the denominator


3f^2*16f+1*16f+()=0

We add all the numbers together, and all the variables

3f^2*16f+1*16f=0

Wy multiply elements

48f^3+16f=0

We do not support efpression: f^3

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