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(3/8)f+1/2=(3/8)f-18
We move all terms to the left:
(3/8)f+1/2-((3/8)f-18)=0
Domain of the equation: 8)f!=0
f!=0/1
f!=0
f∈R
Domain of the equation: 8)f-18)!=0We add all the numbers together, and all the variables
f!=0/1
f!=0
f∈R
(+3/8)f-((+3/8)f-18)+1/2=0
We multiply parentheses
3f^2-((+3/8)f-18)+1/2=0
We calculate fractions
3f^2+()/8f-18)*2)+8f/8f-18)*2)=0
We calculate fractions
3f^2+(()*8f)/64f^2+(-18)*2)+8f*8f)/64f^2=0
We multiply all the terms by the denominator
3f^2*64f^2+(()*8f)+(-18)*2)+8f*8f)=0
We calculate terms in parentheses: +(()*8f), so:Wy multiply elements
()*8f
192f^4+(()*8f)+(-18)*2)+8f*8f)=0
We get rid of parentheses
192f^4+(()*8f)-18)*2)+8f*8f=0
We calculate terms in parentheses: +(()*8f), so:We do not support efpression: f^4
()*8f
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