(3/8)x-(1/3)+6=(1/6)x

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Solution for (3/8)x-(1/3)+6=(1/6)x equation: 



(3/8)x-(1/3)+6=(1/6)x

We move all terms to the left:

(3/8)x-(1/3)+6-((1/6)x)=0



Domain of the equation: 8)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 6)x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+3/8)x-((+1/6)x)+6-(+1/3)=0

We multiply parentheses

3x^2-((+1/6)x)+6-(+1/3)=0

We get rid of parentheses

3x^2-((+1/6)x)+6-1/3=0

We calculate fractions


3x^2+()/6x)*3)+(-6x)/6x)*3)+6=0

We can not solve this equation

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