(3/m-2/9)/(1/3+4/m2)

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Solution for (3/m-2/9)/(1/3+4/m2) equation: 


D( m )

m^2 = 0

m = 0

4/(m^2)+1/3 = 0

m^2 = 0

m^2 = 0

1*m^2 = 0 // : 1

m^2 = 0

m = 0

m = 0

m = 0

4/(m^2)+1/3 = 0

4/(m^2)+1/3 = 0

4*m^-2 = -1/3 // : 4

m^-2 = -1/12

-2 < 0

1/(m^2) = -1/12 // * m^2

1 = -1/12*m^2 // : -1/12

-12 = m^2

m in (-oo:0) U (0:+oo)

(3/m-(2/9))/(4/(m^2)+1/3) = 0

(3/m-2/9)/(4/(m^2)+1/3) = 0

(3*m^-1-2/9)/(4*m^-2+1/3) = 0

3*m^-1 = 2/9 // : 3

m^-1 = 2/27

-1 < 0

1/(m^1) = 2/27 // * m^1

1 = 2/27*m^1 // : 2/27

27/2 = m^1

m = 27/2

m = 27/2

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