(3/m-4)+(1/3(m-4))=6/m

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Solution for (3/m-4)+(1/3(m-4))=6/m equation:



(3/m-4)+(1/3(m-4))=6/m
We move all terms to the left:
(3/m-4)+(1/3(m-4))-(6/m)=0
Domain of the equation: m-4)!=0
m∈R
Domain of the equation: 3(m-4))!=0
m∈R
Domain of the equation: m)!=0
m!=0/1
m!=0
m∈R
We add all the numbers together, and all the variables
(3/m-4)+(1/3(m-4))-(+6/m)=0
We get rid of parentheses
3/m+(1/3(m-4))-6/m-4=0
We calculate fractions
(-18mm/(3m^2m+((1*m)/(3m^2m-4=0
We can not solve this equation

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