(3/n)+3=(4/n)+1

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Solution for (3/n)+3=(4/n)+1 equation: 



(3/n)+3=(4/n)+1

We move all terms to the left:

(3/n)+3-((4/n)+1)=0



Domain of the equation: n)!=0

n!=0/1

n!=0

n∈R





Domain of the equation: n)+1)!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

(+3/n)-((+4/n)+1)+3=0

We get rid of parentheses

3/n-((+4/n)+1)+3=0

We calculate fractions


3n/n^2+(-((+4*n)/n^2+3=0

We add all the numbers together, and all the variables

3n/n^2+(-((+4n)/n^2+3=0

We calculate fractions

We do not support enpression: n^4

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