(3/n-2)+(8-n+8)=(3+8/n-2+n+8)

Solution for (3/n-2)+(8-n+8)=(3+8/n-2+n+8) equation:

(3/n-2)+(8-n+8)=(3+8/n-2+n+8)

We move all terms to the left:

(3/n-2)+(8-n+8)-((3+8/n-2+n+8))=0


Domain of the equation: n-2)!=0

n∈R



Domain of the equation: n-2+n+8))!=0

We move all terms containing n to the left, all other terms to the right

n+n+8))!=2

n∈R


We add all the numbers together, and all the variables

(3/n-2)+(-1n+16)-((n+8/n+9))=0

We get rid of parentheses

3/n-1n-((n+8/n+9))-2+16=0

We calculate fractions


-1n+3n/n^2+(-((n+8*n)/n^2-2+16=0

We add all the numbers together, and all the variables

-1n+3n/n^2+(-((+9n)/n^2-2+16=0

We calculate fractions

We do not support enpression: n^4