(3/r2-5r)+(3/r2+7r)-(1/r2+2r-35)

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Solution for (3/r2-5r)+(3/r2+7r)-(1/r2+2r-35) equation: 


D( r )

r^2 = 0

r^2 = 0

r^2 = 0

1*r^2 = 0 // : 1

r^2 = 0

r = 0

r in (-oo:0) U (0:+oo)

7*r-(5*r)-(2*r)+3/(r^2)+3/(r^2)-(1/(r^2))+35 = 0

7*r-5*r-2*r+3/(r^2)+3/(r^2)-r^-2+35 = 0

5*r^-2 = -35 // : 5

r^-2 = -7

-2 < 0

1/(r^2) = -7 // * r^2

1 = -7*r^2 // : -7

-1/7 = r^2

r belongs to the empty set

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