(3/x)+(1/x+4)=1/7

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Solution for (3/x)+(1/x+4)=1/7 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3/x+1/x+4 = 1/7 // - 1/7

3/x+1/x-(1/7)+4 = 0

3/x+1/x-1/7+4 = 0

4*x^-1 = -27/7 // : 4

x^-1 = -27/28

-1 < 0

1/(x^1) = -27/28 // * x^1

1 = -27/28*x^1 // : -27/28

-28/27 = x^1

x = -28/27

x = -28/27

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