(3/x)+(2/(x+1)=5

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Solution for (3/x)+(2/(x+1)=5 equation: 



(3/x)+(2/(x+1)=5

We move all terms to the left:

(3/x)+(2/(x+1)-(5)=0



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: (x+1)-5!=0

We move all terms containing x to the left, all other terms to the right

(x+1)!=5

x∈R



We add all the numbers together, and all the variables

(+3/x)+(2/(x+1)-5=0

We get rid of parentheses

3/x+(2/(x+1)-5=0

We calculate fractions


(3x-2)/(x^2+x-5)+((2*x)/(x^2+x-5)=0



We calculate terms in parentheses: +((2*x)/(x^2+x-5), so:

(2*x)/(x^2+x-5

We add all the numbers together, and all the variables

(+2x)/(x^2+x-5

We multiply all the terms by the denominator


(+2x)

We get rid of parentheses

2x

Back to the equation:

+(2x)



We add all the numbers together, and all the variables

2x+(3x-2)/(x^2+x-5)=0

We multiply all the terms by the denominator


2x*(x^2+x-5)+(3x-2)=0

We multiply parentheses

2x^3+2x^2-10x+(3x-2)=0

We get rid of parentheses

2x^3+2x^2-10x+3x-2=0

We do not support expression: x^3

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