(3/x)+(2/x)=1/(x-4)

Solution for (3/x)+(2/x)=1/(x-4) equation:

(3/x)+(2/x)=1/(x-4)

We move all terms to the left:

(3/x)+(2/x)-(1/(x-4))=0


Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R



Domain of the equation: (x-4))!=0

x∈R


We add all the numbers together, and all the variables

(+3/x)+(+2/x)-(1/(x-4))=0

We get rid of parentheses

3/x+2/x-(1/(x-4))=0

We calculate fractions


-3x^2)+(-(1*x)/(-3x^2)+(2*(x-4))+3)/(=0


We calculate terms in parentheses: +(2*(x-4)), so:

2*(x-4)

We multiply parentheses

2x-8

Back to the equation:

+(2x-8)


We add all the numbers together, and all the variables

-3x^2)+(-(+x)/(-3x^2)+(2x-8)+3)/(=0

We get rid of parentheses

-3x^2)+(-(+x)/(-3x^2)+2x-8+3)/(=0

We calculate fractions


-3x^2)+(+(-(+x)*()/((-3x^2)*()+(-3x^2)+3)*()/((-3x^2)*()+2x-8=0

We can not solve this equation