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(3/x)+(3/x+4)=(3x-9/x-4)
We move all terms to the left:
(3/x)+(3/x+4)-((3x-9/x-4))=0
Domain of the equation: x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: x+4)!=0
x∈R
Domain of the equation: x-4))!=0We add all the numbers together, and all the variables
x∈R
(+3/x)+(3/x+4)-((3x-9/x-4))=0
We get rid of parentheses
3/x+3/x-((3x-9/x-4))+4=0
We calculate fractions
3x/x^2+(-((3x-9*x)/x^2+4=0
We add all the numbers together, and all the variables
3x/x^2+(-((-6x)/x^2+4=0
We calculate fractions
We do not support expression: x^4
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