(3/x)+2=(4/5x)+(21/10)

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Solution for (3/x)+2=(4/5x)+(21/10) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3/x+2 = (4/5)*x+21/10 // - (4/5)*x+21/10

3/x-((4/5)*x)-(21/10)+2 = 0

(-4/5)*x+3/x-21/10+2 = 0

3*x^-1-4/5*x^1-1/10*x^0 = 0

(3*x^0-4/5*x^2-1/10*x^1)/(x^1) = 0 // * x^2

x^1*(3*x^0-4/5*x^2-1/10*x^1) = 0

x^1

(-4/5)*x^2+(-1/10)*x+3 = 0

(-4/5)*x^2+(-1/10)*x+3 = 0

DELTA = (-1/10)^2-(3*4*(-4/5))

DELTA = 961/100

DELTA > 0

x = ((961/100)^(1/2)-(-1/10))/(2*(-4/5)) or x = (-(-1/10)-(961/100)^(1/2))/(2*(-4/5))

x = -2 or x = 15/8

x in { -2, 15/8} 

x in { -2, 15/8 }

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