(3/x)+2=(5/2x)+(17/8)

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Solution for (3/x)+2=(5/2x)+(17/8) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3/x+2 = (5/2)*x+17/8 // - (5/2)*x+17/8

3/x-((5/2)*x)-(17/8)+2 = 0

(-5/2)*x+3/x-17/8+2 = 0

3*x^-1-5/2*x^1-1/8*x^0 = 0

(3*x^0-5/2*x^2-1/8*x^1)/(x^1) = 0 // * x^2

x^1*(3*x^0-5/2*x^2-1/8*x^1) = 0

x^1

(-5/2)*x^2+(-1/8)*x+3 = 0

(-5/2)*x^2+(-1/8)*x+3 = 0

DELTA = (-1/8)^2-(3*4*(-5/2))

DELTA = 1921/64

DELTA > 0

x = ((1921/64)^(1/2)-(-1/8))/(2*(-5/2)) or x = (-(-1/8)-(1921/64)^(1/2))/(2*(-5/2))

x = ((1921/64)^(1/2)+1/8)/(-5) or x = (1/8-(1921/64)^(1/2))/(-5)

x in { ((1921/64)^(1/2)+1/8)/(-5), (1/8-(1921/64)^(1/2))/(-5)} 

x in { ((1921/64)^(1/2)+1/8)/(-5), (1/8-(1921/64)^(1/2))/(-5) }

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