(3/x)+3=(3/4x)+25/8

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Solution for (3/x)+3=(3/4x)+25/8 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3/x+3 = (3/4)*x+25/8 // - (3/4)*x+25/8

3/x-((3/4)*x)-(25/8)+3 = 0

(-3/4)*x+3/x-25/8+3 = 0

3*x^-1-3/4*x^1-1/8*x^0 = 0

(3*x^0-3/4*x^2-1/8*x^1)/(x^1) = 0 // * x^2

x^1*(3*x^0-3/4*x^2-1/8*x^1) = 0

x^1

(-3/4)*x^2+(-1/8)*x+3 = 0

(-3/4)*x^2+(-1/8)*x+3 = 0

DELTA = (-1/8)^2-(3*4*(-3/4))

DELTA = 577/64

DELTA > 0

x = ((577/64)^(1/2)-(-1/8))/(2*(-3/4)) or x = (-(-1/8)-(577/64)^(1/2))/(2*(-3/4))

x = -2/3*((577/64)^(1/2)+1/8) or x = -2/3*(1/8-(577/64)^(1/2))

x in { -2/3*((577/64)^(1/2)+1/8), -2/3*(1/8-(577/64)^(1/2))} 

x in { -2/3*((577/64)^(1/2)+1/8), -2/3*(1/8-(577/64)^(1/2)) }

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