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(3/x)+3=4x-3
We move all terms to the left:
(3/x)+3-(4x-3)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+3/x)-(4x-3)+3=0
We get rid of parentheses
3/x-4x+3+3=0
We multiply all the terms by the denominator
-4x*x+3*x+3*x+3=0
We add all the numbers together, and all the variables
6x-4x*x+3=0
Wy multiply elements
-4x^2+6x+3=0
a = -4; b = 6; c = +3;
Δ = b2-4ac
Δ = 62-4·(-4)·3
Δ = 84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{84}=\sqrt{4*21}=\sqrt{4}*\sqrt{21}=2\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{21}}{2*-4}=\frac{-6-2\sqrt{21}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{21}}{2*-4}=\frac{-6+2\sqrt{21}}{-8} $
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