(3/x+5)-(4x+1/x-5)

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Solution for (3/x+5)-(4x+1/x-5) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3/x-(4*x)-(1/x)+5+5 = 0

3/x-4*x-x^-1+5+5 = 0

2*x^-1-4*x^1+10*x^0 = 0

(10*x^1-4*x^2+2*x^0)/(x^1) = 0 // * x^2

x^1*(10*x^1-4*x^2+2*x^0) = 0

x^1

10*x-4*x^2+2 = 0

10*x-4*x^2+2 = 0

DELTA = 10^2-(-4*2*4)

DELTA = 132

DELTA > 0

x = (132^(1/2)-10)/(-4*2) or x = (-132^(1/2)-10)/(-4*2)

x = (2*33^(1/2)-10)/(-8) or x = (-2*33^(1/2)-10)/(-8)

x in { (2*33^(1/2)-10)/(-8), (-2*33^(1/2)-10)/(-8)}

x in { (2*33^(1/2)-10)/(-8), (-2*33^(1/2)-10)/(-8) }

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