(3/x-5)=(-3/x+4)+(9/(x-5)(x+4))

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Solution for (3/x-5)=(-3/x+4)+(9/(x-5)(x+4)) equation:


D( x )

x-5 = 0

x = 0

x-5 = 0

x-5 = 0

x-5 = 0 // + 5

x = 5

x = 0

x = 0

x in (-oo:0) U (0:5) U (5:+oo)

3/x-5 = (9/(x-5))*(x+4)-3/x+4 // - (9/(x-5))*(x+4)-3/x+4

3/x-((9/(x-5))*(x+4))-(-3/x)-5-4 = 0

3/x-9*(x+4)*(x-5)^-1+3*x^-1-5-4 = 0

(-9*(x+4))/(x-5)+3/x+3/x-5-4 = 0

(-9*x*(x+4))/(x*(x-5))+(3*(x-5))/(x*(x-5))+(3*(x-5))/(x*(x-5))+(-5*x*(x-5))/(x*(x-5))+(-4*x*(x-5))/(x*(x-5)) = 0

3*(x-5)-9*x*(x+4)+3*(x-5)-5*x*(x-5)-4*x*(x-5) = 0

3*x-9*x^2-5*x^2-4*x^2-33*x+25*x+20*x-15-15 = 0

25*x-9*x^2-5*x^2-4*x^2-30*x+20*x-30 = 0

20*x-14*x^2-4*x^2-5*x-30 = 0

15*x-18*x^2-30 = 0

15*x-18*x^2-30 = 0

3*(5*x-6*x^2-10) = 0

5*x-6*x^2-10 = 0

DELTA = 5^2-(-10*(-6)*4)

DELTA = -215

DELTA < 0

3 = 0

3/(x*(x-5)) = 0

3/(x*(x-5)) = 0 // * x*(x-5)

3 = 0

x belongs to the empty set

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