(3/y)+(2/5)=19/20

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Solution for (3/y)+(2/5)=19/20 equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

3/y+2/5 = 19/20 // - 19/20

3/y+2/5-(19/20) = 0

3/y+2/5-19/20 = 0

3*y^-1 = 11/20 // : 3

y^-1 = 11/60

-1 < 0

1/(y^1) = 11/60 // * y^1

1 = 11/60*y^1 // : 11/60

60/11 = y^1

y = 60/11

y = 60/11

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