(3/y)-(3/(y-4))-4=0

Solution for (3/y)-(3/(y-4))-4=0 equation:

D( y )

y = 0

y-4 = 0

y = 0

y = 0

y-4 = 0

y-4 = 0

y-4 = 0 // + 4

y = 4

y in (-oo:0) U (0:4) U (4:+oo)

3/y-(3/(y-4))-4 = 0

3/y-3*(y-4)^-1-4 = 0

3/y-3/(y-4)-4 = 0

(-3*y)/(y*(y-4))+(3*(y-4))/(y*(y-4))+(-4*y*(y-4))/(y*(y-4)) = 0

3*(y-4)-4*y*(y-4)-3*y = 0

16*y-4*y^2-12 = 0

16*y-4*y^2-12 = 0

4*(4*y-y^2-3) = 0

4*y-y^2-3 = 0

DELTA = 4^2-(-3*(-1)*4)

DELTA = 4

DELTA > 0

y = (4^(1/2)-4)/(-1*2) or y = (-4^(1/2)-4)/(-1*2)

y = 1 or y = 3

4*(y-1)*(y-3) = 0

(4*(y-1)*(y-3))/(y*(y-4)) = 0

(4*(y-1)*(y-3))/(y*(y-4)) = 0 // * y*(y-4)

4*(y-1)*(y-3) = 0

( y-1 )

y-1 = 0 // + 1

y = 1

( y-3 )

y-3 = 0 // + 3

y = 3

y in { 1, 3 }