(3/y-2)-(1/y+3)

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Solution for (3/y-2)-(1/y+3) equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

3/y-(1/y)-3-2 = 0

3/y-y^-1-3-2 = 0

2*y^-1 = 5 // : 2

y^-1 = 5/2

-1 < 0

1/(y^1) = 5/2 // * y^1

1 = 5/2*y^1 // : 5/2

2/5 = y^1

y = 2/5

y = 2/5

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