(3/y-2)=(1/y)+1

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Solution for (3/y-2)=(1/y)+1 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

3/y-2 = 1/y+1 // - 1/y+1

3/y-(1/y)-2-1 = 0

3/y-y^-1-2-1 = 0

2*y^-1 = 3 // : 2

y^-1 = 3/2

-1 < 0

1/(y^1) = 3/2 // * y^1

1 = 3/2*y^1 // : 3/2

2/3 = y^1

y = 2/3

y = 2/3

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