(3/z)-(1/5)=1/2

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Solution for (3/z)-(1/5)=1/2 equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

3/z-(1/5) = 1/2 // - 1/2

3/z-(1/5)-(1/2) = 0

3/z-1/5-1/2 = 0

3*z^-1 = 7/10 // : 3

z^-1 = 7/30

-1 < 0

1/(z^1) = 7/30 // * z^1

1 = 7/30*z^1 // : 7/30

30/7 = z^1

z = 30/7

z = 30/7

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