(3/z)=(9/z)-(1/3)

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Solution for (3/z)=(9/z)-(1/3) equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

3/z = 9/z-(1/3) // - 9/z-(1/3)

3/z-(9/z)+1/3 = 0

3/z-9*z^-1+1/3 = 0

-6*z^-1 = -1/3 // : -6

z^-1 = 1/18

-1 < 0

1/(z^1) = 1/18 // * z^1

1 = 1/18*z^1 // : 1/18

18 = z^1

z = 18

z = 18

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