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(30+1x)(200-5x)=0
We add all the numbers together, and all the variables
(x+30)(-5x+200)=0
We multiply parentheses ..
(-5x^2+200x-150x+6000)=0
We get rid of parentheses
-5x^2+200x-150x+6000=0
We add all the numbers together, and all the variables
-5x^2+50x+6000=0
a = -5; b = 50; c = +6000;
Δ = b2-4ac
Δ = 502-4·(-5)·6000
Δ = 122500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{122500}=350$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-350}{2*-5}=\frac{-400}{-10} =+40 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+350}{2*-5}=\frac{300}{-10} =-30 $
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