(30+2x)(14+2x)=1536

Solution for (30+2x)(14+2x)=1536 equation:

(30+2x)(14+2x)=1536

We move all terms to the left:

(30+2x)(14+2x)-(1536)=0

We add all the numbers together, and all the variables

(2x+30)(2x+14)-1536=0

We multiply parentheses ..

(+4x^2+28x+60x+420)-1536=0

We get rid of parentheses

4x^2+28x+60x+420-1536=0

We add all the numbers together, and all the variables

4x^2+88x-1116=0

a = 4; b = 88; c = -1116;
Δ = b2-4ac
Δ = 882-4·4·(-1116)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-160}{2*4}=\frac{-248}{8}
=-31
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+160}{2*4}=\frac{72}{8}
=9
$