(30+2x)(16+2x)=1632

Solution for (30+2x)(16+2x)=1632 equation:

(30+2x)(16+2x)=1632

We move all terms to the left:

(30+2x)(16+2x)-(1632)=0

We add all the numbers together, and all the variables

(2x+30)(2x+16)-1632=0

We multiply parentheses ..

(+4x^2+32x+60x+480)-1632=0

We get rid of parentheses

4x^2+32x+60x+480-1632=0

We add all the numbers together, and all the variables

4x^2+92x-1152=0

a = 4; b = 92; c = -1152;
Δ = b2-4ac
Δ = 922-4·4·(-1152)
Δ = 26896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{26896}=164$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(92)-164}{2*4}=\frac{-256}{8}
=-32
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(92)+164}{2*4}=\frac{72}{8}
=9
$