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(30+2x)(40+2x)=4200
We move all terms to the left:
(30+2x)(40+2x)-(4200)=0
We add all the numbers together, and all the variables
(2x+30)(2x+40)-4200=0
We multiply parentheses ..
(+4x^2+80x+60x+1200)-4200=0
We get rid of parentheses
4x^2+80x+60x+1200-4200=0
We add all the numbers together, and all the variables
4x^2+140x-3000=0
a = 4; b = 140; c = -3000;
Δ = b2-4ac
Δ = 1402-4·4·(-3000)
Δ = 67600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{67600}=260$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(140)-260}{2*4}=\frac{-400}{8} =-50 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(140)+260}{2*4}=\frac{120}{8} =15 $
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