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(30+2x)(15+2x)=800
We move all terms to the left:
(30+2x)(15+2x)-(800)=0
We add all the numbers together, and all the variables
(2x+30)(2x+15)-800=0
We multiply parentheses ..
(+4x^2+30x+60x+450)-800=0
We get rid of parentheses
4x^2+30x+60x+450-800=0
We add all the numbers together, and all the variables
4x^2+90x-350=0
a = 4; b = 90; c = -350;
Δ = b2-4ac
Δ = 902-4·4·(-350)
Δ = 13700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13700}=\sqrt{100*137}=\sqrt{100}*\sqrt{137}=10\sqrt{137}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-10\sqrt{137}}{2*4}=\frac{-90-10\sqrt{137}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+10\sqrt{137}}{2*4}=\frac{-90+10\sqrt{137}}{8} $
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