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(30+2x)(24+2x)=1080
We move all terms to the left:
(30+2x)(24+2x)-(1080)=0
We add all the numbers together, and all the variables
(2x+30)(2x+24)-1080=0
We multiply parentheses ..
(+4x^2+48x+60x+720)-1080=0
We get rid of parentheses
4x^2+48x+60x+720-1080=0
We add all the numbers together, and all the variables
4x^2+108x-360=0
a = 4; b = 108; c = -360;
Δ = b2-4ac
Δ = 1082-4·4·(-360)
Δ = 17424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{17424}=132$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(108)-132}{2*4}=\frac{-240}{8} =-30 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(108)+132}{2*4}=\frac{24}{8} =3 $
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