(30-(2x+6))+(2x+6)=30x2

Solution for (30-(2x+6))+(2x+6)=30x2 equation:

(30-(2x+6))+(2x+6)=30x^2

We move all terms to the left:

(30-(2x+6))+(2x+6)-(30x^2)=0

determiningTheFunctionDomain
-30x^2+(30-(2x+6))+(2x+6)=0

We get rid of parentheses

-30x^2+(30-(2x+6))+2x+6=0


We calculate terms in parentheses: +(30-(2x+6)), so:

30-(2x+6)

determiningTheFunctionDomain
-(2x+6)+30

We get rid of parentheses

-2x-6+30

We add all the numbers together, and all the variables

-2x+24

Back to the equation:

+(-2x+24)


We add all the numbers together, and all the variables

-30x^2+2x+(-2x+24)+6=0

We get rid of parentheses

-30x^2+2x-2x+24+6=0

We add all the numbers together, and all the variables

-30x^2+30=0

a = -30; b = 0; c = +30;
Δ = b2-4ac
Δ = 02-4·(-30)·30
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*-30}=\frac{-60}{-60}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*-30}=\frac{60}{-60}
=-1
$