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(30-x)+(4x-6)+(2x+6)=180
We move all terms to the left:
(30-x)+(4x-6)+(2x+6)-(180)=0
We add all the numbers together, and all the variables
(-1x+30)+(4x-6)+(2x+6)-180=0
We get rid of parentheses
-1x+4x+2x+30-6+6-180=0
We add all the numbers together, and all the variables
5x-150=0
We move all terms containing x to the left, all other terms to the right
5x=150
x=150/5
x=30
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