(30-x)+(4x-6)+(2x-16)=180

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Solution for (30-x)+(4x-6)+(2x-16)=180 equation: 



(30-x)+(4x-6)+(2x-16)=180

We move all terms to the left:

(30-x)+(4x-6)+(2x-16)-(180)=0

We add all the numbers together, and all the variables

(-1x+30)+(4x-6)+(2x-16)-180=0

We get rid of parentheses

-1x+4x+2x+30-6-16-180=0

We add all the numbers together, and all the variables

5x-172=0

We move all terms containing x to the left, all other terms to the right

5x=172

x=172/5

x=34+2/5

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