(30-z)/5=-z

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Solution for (30-z)/5=-z equation:



(30-z)/5=-z
We move all terms to the left:
(30-z)/5-(-z)=0
We add all the numbers together, and all the variables
(-1z+30)/5-(-1z)=0
We get rid of parentheses
(-1z+30)/5+1z=0
We multiply all the terms by the denominator
(-1z+30)+1z*5=0
Wy multiply elements
(-1z+30)+5z=0
We get rid of parentheses
-1z+5z+30=0
We add all the numbers together, and all the variables
4z+30=0
We move all terms containing z to the left, all other terms to the right
4z=-30
z=-30/4
z=-7+1/2

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