(300-3x)/10+20x=1000

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Solution for (300-3x)/10+20x=1000 equation:



(300-3x)/10+20x=1000
We move all terms to the left:
(300-3x)/10+20x-(1000)=0
We add all the numbers together, and all the variables
(-3x+300)/10+20x-1000=0
We add all the numbers together, and all the variables
20x+(-3x+300)/10-1000=0
We multiply all the terms by the denominator
20x*10+(-3x+300)-1000*10=0
We add all the numbers together, and all the variables
20x*10+(-3x+300)-10000=0
Wy multiply elements
200x+(-3x+300)-10000=0
We get rid of parentheses
200x-3x+300-10000=0
We add all the numbers together, and all the variables
197x-9700=0
We move all terms containing x to the left, all other terms to the right
197x=9700
x=9700/197
x=49+47/197

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