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(300-3x)x=0
We add all the numbers together, and all the variables
(-3x+300)x=0
We multiply parentheses
-3x^2+300x=0
a = -3; b = 300; c = 0;
Δ = b2-4ac
Δ = 3002-4·(-3)·0
Δ = 90000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{90000}=300$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(300)-300}{2*-3}=\frac{-600}{-6} =+100 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(300)+300}{2*-3}=\frac{0}{-6} =0 $
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