(300x)+(65(x/10))=18000000

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Solution for (300x)+(65(x/10))=18000000 equation: 



(300x)+(65(x/10))=18000000

We move all terms to the left:

(300x)+(65(x/10))-(18000000)=0

We add all the numbers together, and all the variables

300x+(65(+x/10))-18000000=0

We multiply all the terms by the denominator


300x*10))+(65(+x-18000000*10))=0

We add all the numbers together, and all the variables

300x*10))+(65(x-180000000))=0

We add all the numbers together, and all the variables

300x*10))+(65(x=0

Wy multiply elements

3000x^2=0

a = 3000; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3000·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6000}=0$

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