(30k-48)-20=(22k-33)+3k

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Solution for (30k-48)-20=(22k-33)+3k equation: 



(30k-48)-20=(22k-33)+3k

We move all terms to the left:

(30k-48)-20-((22k-33)+3k)=0

We get rid of parentheses

30k-((22k-33)+3k)-48-20=0



We calculate terms in parentheses: -((22k-33)+3k), so:

(22k-33)+3k

We add all the numbers together, and all the variables

3k+(22k-33)

We get rid of parentheses

3k+22k-33

We add all the numbers together, and all the variables

25k-33

Back to the equation:

-(25k-33)



We add all the numbers together, and all the variables

30k-(25k-33)-68=0

We get rid of parentheses

30k-25k+33-68=0

We add all the numbers together, and all the variables

5k-35=0

We move all terms containing k to the left, all other terms to the right

5k=35

k=35/5

k=7

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