(30x2+6x)=(-3x)

Solution for (30x2+6x)=(-3x) equation:

(30x^2+6x)=(-3x)

We move all terms to the left:

(30x^2+6x)-((-3x))=0

We get rid of parentheses

30x^2+6x-((-3x))=0


We calculate terms in parentheses: -((-3x)), so:

(-3x)

We get rid of parentheses

-3x

Back to the equation:

-(-3x)


We get rid of parentheses

30x^2+6x+3x=0

We add all the numbers together, and all the variables

30x^2+9x=0

a = 30; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·30·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*30}=\frac{-18}{60}
=-3/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*30}=\frac{0}{60}
=0
$