(31x-2/4x-9)12+3=(42x/3+9x)1+36

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Solution for (31x-2/4x-9)12+3=(42x/3+9x)1+36 equation: 



(31x-2/4x-9)12+3=(42x/3+9x)1+36

We move all terms to the left:

(31x-2/4x-9)12+3-((42x/3+9x)1+36)=0



Domain of the equation: 4x-9)12!=0

x∈R





Domain of the equation: 3+9x)1+36)!=0

We move all terms containing x to the left, all other terms to the right

9x)1+36)!=-3

x!=-3/1

x!=-3

x∈R



We add all the numbers together, and all the variables

(31x-2/4x-9)12-((+9x+42x/3)1+36)+3=0

We multiply parentheses

372x-24x-((+9x+42x/3)1+36)-108+3=0

We multiply all the terms by the denominator


372x*3)1+36)-24x*3)1+36)-((+9x+42x-108*3)1+36)+3*3)1+36)=0

We add all the numbers together, and all the variables

372x*3)1+36)-24x*3)1+36)-((51x-324)1+36)+3*3)1+36)=0

Wy multiply elements

10044x^4=0

We do not support expression: x^4

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