(3200+2500-x)/(2100+1500-x)=2

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Solution for (3200+2500-x)/(2100+1500-x)=2 equation: 


D( x )

1500-x+2100 = 0

1500-x+2100 = 0

1500-x+2100 = 0

3600-x = 0 // - 3600

-x = -3600 // * -1

x = 3600

x in (-oo:3600) U (3600:+oo)

(2500-x+3200)/(1500-x+2100) = 2 // - 2

(2500-x+3200)/(1500-x+2100)-2 = 0

(5700-x)/(3600-x)-2 = 0

(5700-x)/(3600-x)+(-2*(3600-x))/(3600-x) = 0

5700-2*(3600-x)-x = 0

x-1500 = 0

(x-1500)/(3600-x) = 0

(x-1500)/(3600-x) = 0 // * 3600-x

x-1500 = 0

x-1500 = 0 // + 1500

x = 1500

x = 1500

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