(32y-87/54)=3y-23(4+6+7+y)

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Solution for (32y-87/54)=3y-23(4+6+7+y) equation:



(32y-87/54)=3y-23(4+6+7+y)
We move all terms to the left:
(32y-87/54)-(3y-23(4+6+7+y))=0
We add all the numbers together, and all the variables
(+32y-87/54)-(3y-23(y+17))=0
We get rid of parentheses
32y-(3y-23(y+17))-87/54=0
We multiply all the terms by the denominator
32y*54-((3y-23(y+17)))*54-87=0
Wy multiply elements
1728y-((3y-23(y+17)))*54-87=0
We move all terms containing y to the left, all other terms to the right
1728y-((3y-23(y+17)))*54=87

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