(33-2x)(26-2x)=540

Solution for (33-2x)(26-2x)=540 equation:

(33-2x)(26-2x)=540

We move all terms to the left:

(33-2x)(26-2x)-(540)=0

We add all the numbers together, and all the variables

(-2x+33)(-2x+26)-540=0

We multiply parentheses ..

(+4x^2-52x-66x+858)-540=0

We get rid of parentheses

4x^2-52x-66x+858-540=0

We add all the numbers together, and all the variables

4x^2-118x+318=0

a = 4; b = -118; c = +318;
Δ = b2-4ac
Δ = -1182-4·4·318
Δ = 8836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8836}=94$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-118)-94}{2*4}=\frac{24}{8}
=3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-118)+94}{2*4}=\frac{212}{8}
=26+1/2
$