(33b-6)-8(4b+1)=-5

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Solution for (33b-6)-8(4b+1)=-5 equation: 



(33b-6)-8(4b+1)=-5

We move all terms to the left:

(33b-6)-8(4b+1)-(-5)=0

We add all the numbers together, and all the variables

(33b-6)-8(4b+1)+5=0

We multiply parentheses

(33b-6)-32b-8+5=0

We get rid of parentheses

33b-32b-6-8+5=0

We add all the numbers together, and all the variables

b-9=0

We move all terms containing b to the left, all other terms to the right

b=9

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