(33b-7)-8(4b+1)=-6

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Solution for (33b-7)-8(4b+1)=-6 equation: 



(33b-7)-8(4b+1)=-6

We move all terms to the left:

(33b-7)-8(4b+1)-(-6)=0

We add all the numbers together, and all the variables

(33b-7)-8(4b+1)+6=0

We multiply parentheses

(33b-7)-32b-8+6=0

We get rid of parentheses

33b-32b-7-8+6=0

We add all the numbers together, and all the variables

b-9=0

We move all terms containing b to the left, all other terms to the right

b=9

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