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(34f-1)f=2
We move all terms to the left:
(34f-1)f-(2)=0
We multiply parentheses
34f^2-1f-2=0
a = 34; b = -1; c = -2;
Δ = b2-4ac
Δ = -12-4·34·(-2)
Δ = 273
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{273}}{2*34}=\frac{1-\sqrt{273}}{68} $$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{273}}{2*34}=\frac{1+\sqrt{273}}{68} $
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