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(35+x)(18+x)=1260
We move all terms to the left:
(35+x)(18+x)-(1260)=0
We add all the numbers together, and all the variables
(x+35)(x+18)-1260=0
We multiply parentheses ..
(+x^2+18x+35x+630)-1260=0
We get rid of parentheses
x^2+18x+35x+630-1260=0
We add all the numbers together, and all the variables
x^2+53x-630=0
a = 1; b = 53; c = -630;
Δ = b2-4ac
Δ = 532-4·1·(-630)
Δ = 5329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5329}=73$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(53)-73}{2*1}=\frac{-126}{2} =-63 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(53)+73}{2*1}=\frac{20}{2} =10 $
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