(35-4x)/2=(8x+9)/3

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Solution for (35-4x)/2=(8x+9)/3 equation: 



(35-4x)/2=(8x+9)/3

We move all terms to the left:

(35-4x)/2-((8x+9)/3)=0

We add all the numbers together, and all the variables

(-4x+35)/2-((8x+9)/3)=0

We calculate fractions


(-4x)/()+(-((8x+9)*2)/()=0



We calculate terms in parentheses: +(-((8x+9)*2)/(), so:

-((8x+9)*2)/(

We multiply all the terms by the denominator


-((8x+9)*2)



We calculate terms in parentheses: -((8x+9)*2), so:

(8x+9)*2

We multiply parentheses

16x+18

Back to the equation:

-(16x+18)



We get rid of parentheses

-16x-18

Back to the equation:

+(-16x-18)



We get rid of parentheses

(-4x)/()-16x-18=0

We multiply all the terms by the denominator


(-4x)-16x*()-18*()=0

We add all the numbers together, and all the variables

(-4x)-16x*()=0

We get rid of parentheses

-4x-16x*()=0

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